How do you find the x, y and z intercepts of a plane?
I have the below solid geometry problem. I do not know how to find the x, y and z intercepts of a plane. The answer to this would be nice but I what I really need is to understand how to do this.
The plane 2x + 3y – 4z = 5 intersects the x axis at (a,0,0), (0,b,0), (0,0,c). The value of a + b + c is?
Thanks.
November 29th, 2010 at 7:32 am
The intercepts occur when the other 2 coordinates are 0. To find the x-intercept, just set y and z equal to 0, and vice versa.
2a = 5
a = 5/2
3b = 5
b = 5/3
-4c = 5
c = -5/4
and I trust you can add them?
November 29th, 2010 at 8:26 am
For intercepts, you simply put 0 for the other two coordinates. Then:
a = 5/2
b = 5/3
c = -5/4
November 29th, 2010 at 8:58 am
(200)
(030)
(00-4) is you matrix coordinate.
It is supposed to intersect at +5.